# What mass of potassium sulfate and how much water do you need to take to prepare 250 grams of a 15% salt solution?

First of all, the mass of the potassium sulfate salt should be determined. To do this, you will need to use the following formula.

W = m r.v. / m r-ra * 100%.

In this formula, the following values were used: m r.v. is the mass of the soluble substance, m solution is the mass of the solution, W is the mass fraction of the salt solution.

m r.h. = m solution * W / 100%.

m salt = 250 * 15/100 = 37.5 g.

It turns out that the mass of the potassium sulfate salt in solution is 37.5 g.

Next, we determine the mass of water.

m solution = m H2O + m salt.

m H2O = m solution – m salt.

That is, in order to determine the mass of water, the mass of salt should be subtracted from the mass of the solution.

m H2O = 250 – 37.5 = 212.5 g.

Next, we determine the volume of water. To do this, use the following formula.

m = p * V.

Where m is the mass of the substance.

p is the density of the connection.

V is the volume of a given substance.

p = 1 g / ml.

V (H2O) = m / p.

V (H2O) = 212.5g / 1g / ml = 212.5ml.

As a result of the solution, a volume of water equal to 212.5 ml was obtained.

Answer: the mass of the potassium sulfate salt is 37.5 g; the volume of water required to prepare the solution is 212.5 g.